Nice job Jonny-- your answer looks good. Unfortunately the site that I found that question on, doesn't work anymore so I don't know what the answer is.
Three Pimps and a Crack Whore
Wednesday, August 14, 2002
Monday, August 12, 2002
A much easier way for me to explain this... (and I'd like to point out that it took me five days to get this... and really.. it shouldn't have..)...
you have a positive value of 30... and a negitive value of five (or a -5)... to combine them acurately to acount for all the money... you have to subtract the 5 from the 30... the math used subtracts 3, but then adds 2... basically, in math terms...
x = 30
y = w + z
w = -3
z = -2
x + y = 30 - 3 - 2
not
x + y = 30 - 3 + 2
flawed math...
The math in that is wrong... or rather, misleading. If you want to know... If the bellhop gives each guy one dollar back, they each paid nine. That's all fine and good. The thing is, to find out the total amount and figure out where the 'missing' dollar is, you actually have to subtract... so instead of adding the two dollars to their total, you subtract the two dollars, to get to 25, which is the actual price of the room. ($30-$5=$25), so... The guys paid 30. They should have paid 25. Each gets one dollar back from the 30, you get 27, but the total should be 25, not 30... that's what happend, the dollar isn't missing... the math is wrong.
Tuesday, August 06, 2002
Three men checked into a hotel room for which they paid $30. The next day, the manager realized that the men had been overcharged. She gave the bellhop $5 to return to the three men. On the way to their room the bellhop decided to keep $2 for himself, and give each of the three men one dollar. The three men had now paid $9 each, or a total of $27. This plus the $2 the bellhop kept makes a total of $29. What happened to the other dollar?